The procedure below can be used to design ventilation systems:
- Calculate heat or cooling load, including sensible and latent heat
- Calculate necessary air shifts according the number of occupants and their activity or any other special process in the rooms
- Calculate air supply temperature
- Calculate circulated mass of air
- Calculate temperature loss in ducts
- Calculate the outputs of components - heaters, coolers, washers, humidifiers
- Calculate boiler or heater size
- Design and calculate the duct system
1. Calculate Heat and Cooling Loads
Calculate heat and cooling loads by- Calculating indoor heat or cooling loads
- Calculating surrounding heat or cooling loads
2. Calculate Air Shifts according the Occupants or any Processes
Calculate the pollution created by persons and their activity and processes.3. Calculate Air Supply Temperature
Calculate air supply temperature. Common guidelines:- For heating, 38 - 50oC (100 - 120oF) may be suitable
- For cooling where the inlets are near occupied zones , 6 - 8oC (10 - 15oF) below room temperature may be suitable
- For cooling where high velocity diffusing jets are used, 17oC (30oF) below room temperature may be suitable
4. Calculate Air Quantity
Air Heating
If air is used for heating, the needed air flow rate may be expressed asqh = Hh / (ρ cp (ts - tr)) (1)
where
qh = volume of air for heating (m3/s)
Hh = heat load (W)
cp = specific heat air (J/kg K)
ts = supply temperature (oC)
tr = room temperature (oC)
ρ = density of air (kg/m3)
Air Cooling
If air is used for cooling, the needed air flow rate may be expressed asqc = Hc / (ρ cp (to - tr)) (2)
where
qc = volume of air for cooling (m3/s)
Hc = cooling load (W)
to = outlet temperature (oC) where to = tr if the air in the room is mixed
Example - Heating Load
If the heat load is Hh = 400 W, supply temperature ts = 30 oC and the room temperature tr = 22 oC, the air flow rate can be calculated as:qh = (400 W) / ((1.2 kg/m3) (1005 J/kg K) ((30 oC) - (22 oC)))
= 0.041 m3/s
= 149 m3/h
Moisture
Humidifying
If the outside air is more humid than the indoor air - then the indoor air can be humidified by supplying air from the outside. The amount of supply air can be calculated asqmh = Qh / (ρ (x1 - x2)) (3)
where
qmh = volume of air for humidifying (m3/s)
Qh = moisture to be supplied (kg/s)
ρ = density of air (kg/m3)
x2 = humidity of room air (kg/kg)
x1 = humidity of supply air (kg/kg)
Dehumidifying
If the outside air is less humid than the indoor air - then the indoor air can be dehumidified by supplying air from the outside. The amount of supply air can be calculated asqmd = Qd / (ρ (x2 - x1)) (4)
where
qmd = volume of air for dehumidifying (m3/s)
Qd = moisture to be dehumidified (kg/s)
Example - Humidifying
If added moisture Qh = 0.003 kg/s, room humidity x1 = 0.001 kg/kg and supply air humidity x2 = 0.008 kg/kg, the amount of air can expressed as:qmh = (0.003 kg/s) / ((1.2 kg/m3) ((0.008 kg/kg)- (0.001 kg/kg)))Alternatively the air quantity is determined by the requirements of occupants or processes.
= 0.36 m3/s
5. Temperature Loss in Ducts
The heat loss from a duct can be calculated asH = A k ((t1 + t2) / 2 - tr ) (5)The heat loss in the air flow can be expressed as
where
H = heat loss (W)
A = area of duct walls (m2)
t1 = initial temperature in duct (oC)
t2 = final temperature in duct (oC)
k = heat loss coefficient of duct walls (W/m2 K) (5.68 W/m2 K for sheet metal ducts, 2.3 W/m2 K for insulated ducts)
tr = surrounding room temperature (oC)
H = 1000 q cp (t1 - t2) (5b)(5) and (5b) can be combined to
where
q = mass of air flowing (kg/s)
cp = specific heat air (kJ/kg K)
H = A k ((t1 + t2) / 2 - tr)) = 1000 q cp (t1 - t2) (5c)Note that for larger temperature drops logarithmic mean temperatures should be used.
6. Selecting Heaters, Washers, Humidifiers and Coolers
Units as heaters, filters etc. must on basis of of air quantity and capacity be selected from manufacture catalogs.7. Boiler
Boiler rating can be expressed asB = H (1 + x) (6)Boiler with correct rating must be selected from manufacture catalogs.
where
B = boiler rating (kW)
H = total heat load of all heater units in system (kW)
x = margin for heating up the system, it is common to use values 0.1 to 0.2
8. Sizing Ducts
Air speed in a duct can be expressed as:v = Q / A (7)Overall pressure loss in ducts can be calculated as
where
v = air velocity (m/s)
Q = air volume (m3/s)
A = cross section of duct (m2)
dpt = dpf + dps + dpc (8)Major pressure loss in ducts due to friction can be calculated as
where
dpt = total pressure loss in system (Pa, N/m2)
dpf = major pressure loss in ducts due to friction (Pa, N/m2)
dps = minor pressure loss in fittings, bends etc. (Pa, N/m2)
dpc = minor pressure loss in components as filters, heaters etc. (Pa, N/m2)
dpf = R l (9)Duct friction resistance per unit length can be calculated as
where
R = duct friction resistance per unit length (Pa, N/m2 per m duct)
l = length of duct (m)
R = λ / dh (ρ v2 / 2) (10)
where
R = pressure loss (Pa, N/m2)
λ = friction coefficient
dh = hydraulic diameter (m)
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